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41 lines
1.8 KiB
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41 lines
1.8 KiB
HTML
<p>给你一个以 <code>(radius, xCenter, yCenter)</code> 表示的圆和一个与坐标轴平行的矩形 <code>(x1, y1, x2, y2)</code> ，其中 <code>(x1, y1)</code> 是矩形左下角的坐标，而 <code>(x2, y2)</code> 是右上角的坐标。</p>
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<p>如果圆和矩形有重叠的部分，请你返回 <code>true</code> ，否则返回 <code>false</code> 。</p>
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<p>换句话说，请你检测是否 <strong>存在</strong> 点 <code>(x<sub>i</sub>, y<sub>i</sub>)</code> ，它既在圆上也在矩形上（两者都包括点落在边界上的情况）。</p>
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<p> </p>
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<p><strong class="example">示例 1 ：</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2020/02/20/sample_4_1728.png" style="width: 258px; height: 167px;" />
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<pre>
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<strong>输入：</strong>radius = 1, xCenter = 0, yCenter = 0, x1 = 1, y1 = -1, x2 = 3, y2 = 1
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<strong>输出：</strong>true
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<strong>解释：</strong>圆和矩形存在公共点 (1,0) 。
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</pre>
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<p><strong class="example">示例 2 ：</strong></p>
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<pre>
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<strong>输入：</strong>radius = 1, xCenter = 1, yCenter = 1, x1 = 1, y1 = -3, x2 = 2, y2 = -1
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<strong>输出：</strong>false
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</pre>
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<p><strong class="example">示例 3 ：</strong></p>
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<img alt="" src="https://assets.leetcode.com/uploads/2020/02/20/sample_2_1728.png" style="width: 150px; height: 135px;" />
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<pre>
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<strong>输入：</strong>radius = 1, xCenter = 0, yCenter = 0, x1 = -1, y1 = 0, x2 = 0, y2 = 1
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<strong>输出：</strong>true
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</pre>
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<p> </p>
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<p><strong>提示：</strong></p>
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<ul>
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<li><code>1 <= radius <= 2000</code></li>
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<li><code>-10<sup>4</sup> <= xCenter, yCenter <= 10<sup>4</sup></code></li>
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<li><code>-10<sup>4</sup> <= x1 < x2 <= 10<sup>4</sup></code></li>
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<li><code>-10<sup>4</sup> <= y1 < y2 <= 10<sup>4</sup></code></li>
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</ul>
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